FormationKulliyadaha iyo jaamacadaha

Waa maxay dadab ah sedjibeke, iyo sidii ay u heli

Waxa a saaraayo, iyo wixii uu Wanqaar

Cube (polyhedron joogto ah ama hexahedron) waa shaqsi aad saddex dhinac-cabbir ah, wejiga kasta - waa square ah, kaas oo, sida aynu ognahay, dhinacyada oo dhan waa u siman yihiin. Dadab ah sedjibeke waa gabal in maraa xarunta of tiradaasi iyo xirmaan danbow symmetrical. In hexahedron midig ayaa dadab 4, oo kulligoodna way wada noqon doonaa siman. Waxaa muhiim ah in aan la isku qaldin ee dadab ah tiradaasi laftiisa ay wejiga dadab ama square, oo ku taala ee salkeeda. Dadab ah saaraayo ka maraa xarunta wajiga iyo xiriirisa geesaha soo horjeeda ee square ah.

Formula in ka heli kartaa dadab ah sedjibeke

polyhedron joogto ah dadab waxaa laga heli karaa formula ah mid aad u fudud in aad rabto in aad xasuusato. D = a√3, halkaas oo D matalaa dadab ah saaraayo ah, iyo - ku laayeen this. Halkan waxaa ku qoran tusaale ka mid ah dhibaatada, halkaas oo ay lagama maarmaan tahay in la helo dadab ah, haddii aad ogtahay in ay la mid tahay dhererka ku laayeen of 2 cm ee. Waa D fudud = 2√3, xitaa ma u baahan tahay si ay u eegaan wax. In labaad tusaale ahaan, ha ku laayeen oo ka mid ah sedjibeke waa loo siman yahay si √3 cm, ka dibna waxaan u hesho D = √3√3 = √9 = 3. Jawaab: D isla'egta 3 cm.

Formula in ka heli kartaa dadab ah saaraayo ah

Diago ku saabsan oo Nahl sidoo kale waxaa laga heli karaa by caanaha. Diagonals, taas oo ah been Wajiyada of 12 xabbadood, oo kulligoodna waa wada siman yahay. Hadda waxaannu xusuusan nahay d = a√2, halkaas oo d - waa u dadab ah square, iyo - Waxaa sidoo kale la saaraayo laayeen ama dhinac oo ka mid ah laba jibbaaran. Si ay u fahmaan meesha this formula waa mid aad u fudud. Ka dib oo dhan, ay labada dhinac ka mid ah square iyo dadab foom xaq-aaqirkii saddexagalka. Seddexda ciyaaryahan Tani waxay kaalin ee shakaal a dadab iyo dhinaca square ah - waa lugaha in ay yihiin dhererka isku mid ah. Ha noo xusuusataan Aragtida ku Theorem, oo dhan hal mar ku dhici doonaan meel. Haddaba dhibaatada: hexahedron laayeen uyeelaysaan kuwo √8 arki, waxaa lagama maarmaan ah in la helo a dadab ee weji. Waxaan ku riday caanaha, iyo waxaan ka heli d = √8 √2 = √16 = 4. Jawaab: The dadab ah saaraayo yahay 4 cm.

Haddii aan ogaan Wajiyada saaraayo ku dadab

Sida laga soo xigtay dhibaato, waxaan la siiyaa oo keliya dadab Wajiyada kuwa si joogto ah polyhedron, oo waa loo siman yahay si, waxaad tidhaahdaan, √2 cm, iyo waxaan u baahan si aad u hesho a dadab of a saaraayo. The formula si ay u xaliyaan dhibaato yar oo ka adag hore. Haddii aan ogaan d, ka dibna waxaan ka heli kartaa darafka saaraayo ah, iyadoo ay ku saleysan our labaad formula d = a√2. Waxaan aad u hesho a = d / √2 = √2 / √2 = 1cm (waa kan ku laayeen). Oo haddaynu og nahay qiimaha this, ka dibna si aad u hesho a dadab ah sedjibeke ma aha wax adag, D = 1√3 = √3. Taasi waa sida aan u xallin our hawsha.

Haddii meel dusha loo yaqaan

geynta soo socda waxay ku salaysan tahay xal raadinta ku qotonta on bedka of saaraayo ah. U qaadan in ay tahay loo siman yahay ilaa 72 cm 2. Si aad u bilawdo, ka heli meesha ka mid ah wajiga, iyo guud ahaan 6. Sidaas, aad u baahan tahay si ay u qaybsadaan 72 6 iyo aad u hesho 12 cm 2. Tani waa mid ka mid ah aagga wajiga. Si aad u hesho cidhifka polyhedron joogto ah, waxaa lagama maarmaan ah in ay dib ugu yeeran formula ah S = 2 a, ka dibna a = √S. Bedel ku soo galay iyo aad u hesho a = √12 (laayeen saaraayo). Oo haddaynu og nahay qiimaha this, oo aan u adag tahay in la helo D a dadab = a√3 = √12 √3 = √36 = 6. Jawaab: The dadab ah sedjibeke waa loo siman yahay ilaa 6 cm 2.

Haddii la yaqaan dhererka saaraayo geesaha

Waxaa jira xaalado taas oo dhibaatada la siiyo oo keliya dhererka cidhifyada saaraayo ah. Markaas waxaa lagama maarmaan ah in ay kala qaybiyaan 12. Taasi waa tirada xisbiyada ee polyhedra caadiga ah. Tusaale ahaan, haddii wadarta dhammaan geesaha waa loo siman yahay ilaa 40, oo dhinac keliya ayuu ku noqon doonaa si siman u 40/12 = 3,333. Waxaan ku riday formula hore iyo aad u hesho jawaabta!

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